abd is a right angle triangle at angle a=90 and ac perpendicular bd show that (1)ab2 =bc.bd (2) ac2=bc.dc
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In triangle ACB
Ab2 = ac2 +bc2
But ac2 = da2- dc2
Ab2 = ad2-dc2+bc2
Ab2 = db2- ab2-( db-bc)2 + bc2
Ab2= db2- ab2- db2- bc2+ 2 dbbc+bc2
2ab2= 2 dbbc
Ab2= dbbc
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