Question

Abdul ledt his home at 7:35am and drove at an average speed of 45km/h arriving at the airport at 8:50am.How far is his home from the airport? ​

Answer 1

$Given \: Average \:of \:speed \:of \:Abdul (s)\\= 45 \:km/hr$

$Time (t) = 7.35 \:am \:to \:8.50 \:a.m \\= 75 \:mi \\= \frac{75}{60}\: hr$

$Let \: distance \:from \:home \:to \:airport= d$

$\boxed { \pink { distance = speed \times time }}$

$Distance (d) = 45 \times \frac{75}{60} \\= 56.25 \:km$

Therefore.,

$\red { distance \:from \:home \:to \:airport}\green {= 56.25 \:km}$

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