Math, asked by dkavyasri13, 1 year ago

Abdul travelled 300km by trains and 200km by taxi, it took 5 hours 30 minutes.but if he travels 260km by train and 240 km by taxi,he takes 6 minutes longer.find the speed of the train and that of the taxi.

Answers

Answered by hukam0685
108

Step-by-step explanation:

Given that:Abdul travelled 300km by trains and 200km by taxi, it took 5 hours 30 minutes.but ifhe travels 260km by train and 240 km by taxi,he takes 6 minutes longer.

To find: find the speed of the train and that of the taxi.

solution: Let the speed of train is x km/hr

and speed of taxi is y km/hr

Since,Travelling time is given in both the cases,calculate the time taken by train and by taxi and form linear equations

Case1: Abdul travelled 300km by trains and 200km by taxi, it took 5 hours 30 minutes.

Time taken by train to cover 300 km with the speed x km/hr

Time= Distance travelled/speed

= 300/x hr

Time taken by taki to travel 200 km,

= 200/y

 \frac{300}{x}  +  \frac{200}{y}  =  \frac{11}{2}   \:  \:  \:  \: eq1\\

Case2: Abdul travels 260km by train and 240 km by taxi,he takes 6 minutes longer..

Time taken by train to cover 260 km with the speed x km/hr

Time= Distance travelled/speed

= 260/x hr

Time taken by taki to travel 240 km,

= 240/y

 \frac{260}{x}  +  \frac{240}{y}  = 5 \: hr \: 36 \: min \\  \\ \frac{260}{x}  +  \frac{240}{y} = 5 \frac{36}{60}  \\  \\ \frac{260}{x}  +  \frac{240}{y} = 5 \frac{3}{5}  \\  \\ \frac{260}{x}  +  \frac{240}{y} =  \frac{28}{5}  \:  \:  \:  \:  \: eq2 \\  \\

Eq1 and 2 can be converted to linear equation

let \\  \\  \frac{1}{x}  = a \\  \\  \frac{1}{y}  = b \\  \\ 300a + 200b =  \frac{11}{2}   \:  \:  \:  \: ...eq3\\  \\ 65a + 60b =  \frac{7}{5}  \:  \:  \:... eq4 \\  \\

On solving these linear equations by elimination method,

Multiply eq3 by 60 and eq4 by 200 and subtract both

60[300a + 200b =  \frac{11}{2}]\\\\18000a+12000b=330   \:  \:  \:  \: ...eq5\\  \\ 200[65a + 60b =  \frac{7}{5}]\\\\ 13000a+12000b=280 \:  \:  \:... eq6\\  \\

Eq5-eq6

5000a=50\\\\a=\frac{50}{5000}\\\\a=\frac{1}{100}\\\\

put the value of a in eq 4

b= 1/80

Now

a =  \frac{1}{100}  \\  \\ b =  \frac{1}{80}  \\  \\

Thus,

 \frac{1}{x}  = a \\  \\  \frac{1}{x}  =  \frac{1}{100}  \\  \\ x = 100 \\  \\ \frac{1}{y}  = b \\  \\  \frac{1}{y}  =  \frac{1}{80}  \\  \\ y = 80 \\ \\

Thus,the speed of train is 100km/hr and speed of taxi is 80 km/hr.

Hope it helps you.

Answered by ItzRadhika
92

Refers to attachment ⚘⚘

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