Physics, asked by rijaabjafar1498, 10 months ago

Abdul while driving to school, computes the average speed fir his trip to be 20kmh^-1. On his return trip along the same route, there is less traffic and the average speed is 30kmh^-1. What is the average speed for Abdul's trip?

Answers

Answered by Anonymous
20

Abdul while driving to school, computes the average speed for his route to be 20 km/hr.

Let us assume that the distance covered by the Abdul is 'x'.

Distance = Speed × Time

d1 = s1 × t1

x = 20 × t1

x/20 = t1 ..............(1st equation)

Also, during traffic his average speed is 30 km/hr.

d2 = s2 × t2

x = 30 × t2

x/30 = t2 ..............(2nd equation)

Average speed is defined as the ratio of total distance covered with respect to total time taken.

Total distance covered by the Abdul = (x + x)km = 2x km

Total time taken = t1 + t2

= x/20 + x/30

= (3x + 2x)/60

= 5x/60

Average speed = 2x/(5x/60)

= (2x × 60)/5

= 24

Therefore, the average speed of the Abdul during the trip is 24 km/hr.

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