Abdul while driving to school computes the average speed for his trip to be 20 km per hour on his return trip along the same route there is less traffic and average speed is 30 km per hour what is the average speed for Abdul trip
Answers
Answer:
80/3 km/hr
Explanation:
DIRECT TRICK
if the speed during forward journey be x and during return journey be y , then average speed will be :-
GOING THROUGH CONCEPT
- let the total distance in the forward journey be 'd'.
Hence, time taken in forward journey = d/24.
and time taken in return journey would be = d/30.
We know, average speed=
Here, total distance = 2d.
Hence, average speed =
Regards
Kshitij
Answer:
while going to school the speed ofabdul= 20kms/h
while going to school the speed ofabdul= 20kms/hand while returning = 30kms/h
while going to school the speed ofabdul= 20kms/hand while returning = 30kms/hnow average speed = [(int. speed +finalspeed)/2]
while going to school the speed ofabdul= 20kms/hand while returning = 30kms/hnow average speed = [(int. speed +finalspeed)/2]= [(20 + 30)/2]kms/h
while going to school the speed ofabdul= 20kms/hand while returning = 30kms/hnow average speed = [(int. speed +finalspeed)/2]= [(20 + 30)/2]kms/h= (50/2)kms/h
while going to school the speed ofabdul= 20kms/hand while returning = 30kms/hnow average speed = [(int. speed +finalspeed)/2]= [(20 + 30)/2]kms/h= (50/2)kms/h= 25 kms/h___ans
while going to school the speed ofabdul= 20kms/hand while returning = 30kms/hnow average speed = [(int. speed +finalspeed)/2]= [(20 + 30)/2]kms/h= (50/2)kms/h= 25 kms/h___ansif satisfied then pls do not markitbrainliest...only give thanksmultipletimes_:)
while going to school the speed ofabdul= 20kms/hand while returning = 30kms/hnow average speed = [(int. speed +finalspeed)/2]= [(20 + 30)/2]kms/h= (50/2)kms/h= 25 kms/h___ansif satisfied then pls do not markitbrainliest...only give thanksmultipletimes_:)THANKS!
it's k