Question

Abdul, while driving to school, computes the average speed for his trip to be 20km h
−1
. On his return trip along the same route, there is less traffic and the average speed is 30km h
−1
. What is the average speed for Abdul's trip?

​

Answer 1

$\bold \pink{Given }$

Abdul, while driving to school, computes the average speed for his trip to be 20 km h-1. On his return trip along the same route, there is less traffic and the average speed is 30 km h-1.

To find

The average speed for Abdul’s trip

As per given data in the question

Average speed from home to school v1av = 20km h-1

Average speed from School to Home v2av = 30km h-1

Our assumptions

The distance Abdul commutes while driving from Home to School = s

Let us assume time taken by Abdul to commutes this distance = t1

Distance Abdul commutes while driving from School to Home = S

Let us assume time taken by Abdul to commutes this distance = t2

Also we know that

The time taken from Home to School t1=S/v1av

Similarly Time taken from School to Home t2=S/v2av

Total distance

Total distance from home to school and backward = 2S——-(i)

Total time taken from home to school and backward (T)=S/20+S/30———-(ii)

$\bold \blue {Formula }$

Speed = Distance / Time

Therefore,

Average Speed(Vav)for covering total distance (2s)=Total Distance/Total Time

So from equations (i) and (ii) we get,

Average Speed(Vav) =2S/(S/20+S/30)

=2S/[30S+20S)/600] =1200S/50S

=24kmh-1

Final answer

$\bold \pink{24kmh-1}$

Answer 2

Explanation:

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