Abdul while driving to school computes the average speed for his trip to be 20 km per hour on his return trip along the same route there is less traffic and average speed is 30 km per hour what is the average speed for abdul's trip
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Answered by
8
average speed =2v1×v2/(v1+v2)
=2×20×30/(20+30)
=1200/50=24km/hr
=2×20×30/(20+30)
=1200/50=24km/hr
rownak2:
but what is the formula
Answered by
5
V1 is equal to initial point and v2 is equal to final point
average speed=2(v1*v2)/(v1+v2)
= 2(600)/(50)
=1200/50
=24km/h
average speed=2(v1*v2)/(v1+v2)
= 2(600)/(50)
=1200/50
=24km/h
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