Abdul while driving to school computes the average speed for his trip be 20km/h on his return trip along the same route there is lees traffic and the average speed 30km/h what is the average speed foe abdul trip?
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Hi dear,
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Let the distance from Abdul's house to school is ' D ' and time taken to reach from home to school is ' T ' and that of coming from school to house it ' t '.
According to question,
For going home to school,
Total distance / Total time taken to cover that distance = average speed
We have , total distance = D and total time taken = T.
So, D / T = 20 km/h
T = Dh / 20 km. ----------------------------- eq.1
Now from coming from school to home,
We have,
total distance = D and time taken = t.
Total distance / Total time taken to cover that distance = Average speed
D / t = 30 km/h
t = Dh / 30 km. -------------------------------- eq.2
Now, for his average speed for total journey,
Total distance = D + D = 2D.
Total time taken = T + t.
Average speed = Total distance / total time taken to cover that distance
= 2D / ( T + t ) ------------------ eq.3
By putting the value of eq.1 and eq.2 in eq.3,
= 2D / ( Dh / 20 km + Dh / 30 km )
3Dh + 2Dh
= 2D / ( -------------------- )
60 km
= 2D / ( 5 Dh / 60 km )
= 2D * 60 km / 5Dh
= 24 km/h.
--------------------------------------------------------------
Let the distance from Abdul's house to school is ' D ' and time taken to reach from home to school is ' T ' and that of coming from school to house it ' t '.
According to question,
For going home to school,
Total distance / Total time taken to cover that distance = average speed
We have , total distance = D and total time taken = T.
So, D / T = 20 km/h
T = Dh / 20 km. ----------------------------- eq.1
Now from coming from school to home,
We have,
total distance = D and time taken = t.
Total distance / Total time taken to cover that distance = Average speed
D / t = 30 km/h
t = Dh / 30 km. -------------------------------- eq.2
Now, for his average speed for total journey,
Total distance = D + D = 2D.
Total time taken = T + t.
Average speed = Total distance / total time taken to cover that distance
= 2D / ( T + t ) ------------------ eq.3
By putting the value of eq.1 and eq.2 in eq.3,
= 2D / ( Dh / 20 km + Dh / 30 km )
3Dh + 2Dh
= 2D / ( -------------------- )
60 km
= 2D / ( 5 Dh / 60 km )
= 2D * 60 km / 5Dh
= 24 km/h.
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