Question

Abdul while driving to school computes the average speed for his trip to be 20 Km/h. On

his return trip along the same rout is less traffic and the average speed is 40 km/h.

What is the average speed for Abdul’s trip ?​

Answer 1

$\huge \red {answer}$

$\large \green {vav = \: average \: velocity \: \: v1 = velocity \: from \: home \: to \: school \: \: v2 = velocity \: from \: school \: to \: home }$

$\bold{given \: v1 = 20 \frac{km}{h} } \: \bold{ and \: v2 \: =40 \frac{km}{h} }$

$\bold{formula \: vav \: = \frac{v1 + v2}{2} } \: \: \: {only \: use \: when \: distance \: is \: same \: in \: both \: velocities}$

$\bold{vav = \frac{20 + 40}{2} } \\ \\ \bold{vav = \frac{60}{2} } \\ \\ \bold{vav = 30 \frac{km}{h} }$

Answer 2

Answer:

60 km

Explanation:

Abdul while driving to School = 20km

his return trip along the same route = +40 km

The average speed - 60 km