Physics, asked by jainrakshit77p7l4hi, 1 year ago

Abdul, while driving to school,computes the average speed for his trip to be 20 km/h.on his return trip along the same route,there is less traffic and the average speed is 40km/h.what is the average speed for abdul's trip?

Answers

Answered by Sanskriti141
20
ANSWER
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let \: the \: distance \: between \: home \: and \: school \: be \: s\\  \\ average \: speed \: for \: home \: to \:school \:  =  \: 24km {h}^{ - 1}  \\  \\ speed \:  =  \frac{distance}{time}   \\  \\ 20 =  \frac{s}{t}  \\  \\ t \:  =  \:  \frac{s}{20} h \\  \\ average \: speed \: for \: school \: to \: home \:  =  \: 40km {h}^{ - 1}  \\  \\ speed \:  = >  \: 40 =  \frac{s}{t} \\  \\ t \:  =  \frac{s}{40}  \\  \\ total \: distance \: travelled \:  = s + s \:  =  \: 2s \\  \\ average \: speed \:  =  \:  \frac{total \: distance \: travelled}{total \: \: time }  \\  \\  =  \frac{s \:  + s}{ \frac{s}{20} +  \frac{s}{40}  }  \\  \\   = \frac{2s}{ \frac{3s}{40} }  \\  \\ =  2s \: \times  \frac{40}{3s}  \\  \\  =  \: 26.666 \: km {h}^{ - 1}   \\  \\  = 26.67 \: km {h}^{ - 1}  \:  \:  \:  \: ans


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#BE BRAINLY
Answered by Shreyansh007
7

Answer:

24km/h

Explanation:

Given :

Method I:  

Let the distance traveled by Abdul from home to school = s km

time taken to reach the school=t1 sec

For Return journey , Abdul cover distance =s km

time=t2 sec

∴ Average speed for forward journey[home - school ] = Total distance/ Total time.

20 km/h =s/t1

∴t1=s/20 h ------eq(1)

 Average speed for backward journey[school -home] = Total distance/ Total time.

30 km/h =s/t2

t2=s/30h -----eq(2)

Average distance for entire journey = Total distance/ Total time

                                                        =(s+s)/[s/20 +s/30]

                                                        =2s/s[1/20+1/30]

                                                         =2x20x30/50

                                                          =24 km/hr

Shortcut method : If equal distance are covered with speeds v1 and v2 then average distance=2v1v2/v1+v2

                          = 2x20x30/50

                           =24km/hr

∴ The average speed for Abdul's trip is 24km/h

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