Question

Abdul, while driving to school, computes the average speed for his trip to be 20 km h . On his return trip along the same route, there is less traffic and the average speed is 30 km h. What is the average speed for Abduls trip?

Answer 1

1st speed= 20kmph
2nd speed= 30kmph
Total speed = (30+20)kmph
=50kmph
No. of speeds = 2
Therefore, average speed= 50÷2 = 25kmph

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Answer 2

Answer:

• The average speed of Abdul is 24 km h ¯¹

Given :

• Average speed in fist trip = 20 km h¯¹

• Average speed in second trip = 30 km h ¯¹

To find :

• Total average speed of Abdul's trip =?

Step-by-step explanation :

Let the distance of the school = s km

Let time to reach the school in first trip = t₁

Let time to reach the school in second trip = t₂

The average speed = Total distance /Time taken

Average speed in first trip = s/t1

20 = s/t₁

t₁ = s/20 h

Average speed in second trip = s/t₂

30 = s/t₂

t₂ = s/30 h

Now total time (t₁ + t₂) = s/20 + s/30

(t₁ + t₂) = 3s + 2s/60 = 5s/60 = s/12

Average speed of both trip = Total distance covered/Total time taken

=2s/(s/12) km h¯¹

= 2s × 12 / s km h ¯¹

= 24 km h ¯¹

Therefore,

The average speed of Abdul is 24 km h¯¹.