Physics, asked by drrajkant, 9 months ago

Abdul while travelling the average speed for his trip 20kms/hrs.
On the return trip along the same boat average speed is 30 kms /hrs. What is the average speed of his entire trip.

Answers

Answered by nikitaagrawal222222
1

Answer:

HELLO GUY!!!

Let the distance traveled by Abdul from home to school = s km

time taken to reach the school=t1 sec

For Return journey , Abdul cover distance =s km

time=t2 sec

∴ Average speed for forward journey[home - school ] = Total distance/ Total time.

20 km/h =s/t1

∴t1=s/20 h ------eq(1)

 Average speed for backward journey[school -home] = Total distance/ Total time.

30 km/h =s/t2

t2=s/30h -----eq(2)

Average distance for entire journey = Total distance/ Total time

                                                        =(s+s)/[s/20 +s/30]

                                                        =2s/s[1/20+1/30]

                                                         =2x20x30/50

                                                          =24 km/hr

Shortcut method : If equal distance are covered with speeds v1 and v2 then average distance=2v1v2/v1+v2

                          = 2x20x30/50

                           =24km/hr

HOPE THISA WILL HELP YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Explanation:

Answered by amoghraj717qtr
0

Answer:

average speed of the ⛵ boat is =(20+30)/2

= 50/2

= 25kmph

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