Question

abe contains green and yellow balls two balls are drawn without replacement the probability of selecting a green wall and then a yellow what is 0.8 the probability of selecting a green Bond first cry 0.5 what is the probability of selecting a yellow wall on the second drug given that the first ball sc.reen ​

Answer 1

Answer:

1.3 is answer follow for more

Answer 2

given probabilities of two scenarios for selecting 2 balls out a number of green and yellow balls without replacement, find probability of selecting yellow on second try if first was green.

Explanation:

1. let the number of green balls be 'g' and number yellow balls be 'y' then the total number of balls is $g+y$.
2. now let A-first ball selected is green , B-second ball selected is yellow and E-first ball selected is green and second ball selected is yellow. then we have,  $P(A)=\frac{g}{g+y} =0.5$            ------(i)                                                                                      

                         $P(B)=\frac{y}{g+y-1}$ ->one less due to selection without replacement

    3.since events A and B are occurring together,

                         $P(E)=P(A).P(B)=0.8$   ----(ii)                                                                

    4.then from (i) and (ii) we get, $P(B)=\frac{0.8}{0.5} = 1.6$ which is not a real value for

        probability. hence, the event is not possible with given data.