Question

Abe is going to plant 54 oak trees and 27 pine trees. Abe would like to plant the trees in rows that all have the same number of trees and are made up of only one type of tree. What is the greatest number of trees Abe can have in each row? How many rows of each tree will he have?

Answer 1

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▶ Question :- Abe is going to plant 54 oak trees and 27 pine trees. Abe would like to plant the trees in rows that all have the same number of trees and are made up of only one type of tree. What is the greatest number of trees Abe can have in each row? How many rows of each tree will he have?


▶ Solution :-

→ There are 27 trees in each row .

→ There is 1 row of Pine trees and 2 rows of Oak tree.



▶ Explanation :-

Abe have two types of the trees i.e., Oak tree and Pine tree.

→ Number of Oak tree = 54 .

→ Number of Pine tree = 27.


A/Q, we have given that Abe wants to plant the trees in rows that all have the same number of trees and are made up of only one type of tree.

So, the greatest number of trees is given by

↪ HCF of 54 and 27 .

→ 54 = 3 × 3 × 3 × 2 .

→ 27 = 3 × 3 × 3.

→ Common factor = 3 × 3 × 3 .

Therefore, HCF = 27.

Hence, there are 27 trees that Abe can plant in each row.

▶ Now, number of rows of Pine tree = 27/27 = 1 rows.


→ Number of rows of Oak tree = 54/27 = 2 rows.



✔✔ Hence, it is solved ✅✅.

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Answer 2

HEY MATE HERE IS YOUR ANSWER

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Given :-

Abe wanted to plant :-

54 oak trees and 27 pine trees.

According to the Question Abe wanted to plant trees in rows and 1 row will have 1 type of plant.

So,
Therefore, The greatest number of trees will find by HCF of 55 and 27

➡️ 54 => 3×3×3×2

➡️ 27=>3×3×3

Therefore,

Common Factor :- 3 × 3 × 3

So,

HCF = 27

Therefore,

27 trees abe can plant in 1 row.


Number of rows of pine trees :- 27/27 => 1

Number of rows of oak tree :- 54/27 = 2


Therefore, Abe plant trees of pine and oak in 3 rows. 2 rows for oak tree and 1 row for pine trees.


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Ansh as ans81