abe is triangle in circle, ab||cd
d is point on circumferance such that dab=25° find aeb
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Step-by-step explanation:
In the given figure join AC and BD then ∠CAD=∠CBD=90
o
∵ Angle is formed by diameter.
Also AB∣∣CD
∴∠BAD=∠ADC=25
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∠BAC=∠BAD+∠CAD=25+90=115
o
∴ ∠ADB=180
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−25−∠BAC=40
o
Also, ∠AEB=∠ADB=40
o
Angle subtended by same chord on the circle are equal.
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