Math, asked by itzbangtanbutterfly, 1 month ago

Abha bought 2 calculators at Rs 900. She sold one at profit of 20% and other at a loss of 20%. If the SP of both calculator was same, then find the CP of each calculator.​

Answers

Answered by Hibah60701
0

Given:

CP OF 2 Calculators=Rs.900

SP of one calculator=20% profit on CP

SP of other calculator=20% loss on CP

To find:

CP of both Calculators

Solution:

Cost Price is the amount in which a person buys the item.

Selling Price is the amount in which a person sells the item.

let the cost price of one calculator be x

let the cost price of other calculator be 900-x

x+(900-x)=900

SP=CP+Profit

SP=CP-Loss

Then the Selling price of costly calculator will be: x\times\frac{80}{100}x×

100

80

{∵ It is selling at loss of 20%)

and the Selling price of another calculator will be: (900 - x)\times\frac{120}{100}(900−x)×

100

120

{∵ It is selling at profit of 20%)

Also it is given that selling price of both calculator is same. So we can write it as:

x\times\frac{80}{100} = (900 - x)\times\frac{120}{100}x×

100

80

=(900−x)×

100

120

2x = 3(900 - x)

2x = 2700 - 3x

x = 540

Then price of other calculator is 900 - 540 = 360.

Hence, the price of one calculators is Rs. 540

the price of other calculator is Rs.360

Answered by akichanbaby650
0

Ans. is given in attached pic...

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