Question

Abhay drives 4km to the north and then 3km to the east. Find the distance between the starting point and the terminating point​

Answer 1

Let, the required distance =x km.

By Pythagoras theorem,

x² =4²+3²

or, x²=16+9

or, x²=25

so, x=5 km Ans.

Answer 2

$\star\:\:\:\bf\large\underline\blue{Question:-}$

• Abhay drives 4km to the North and then 3km to the East.Find the distance between the starting point and terminating point.

$\star\:\:\:\bf\large\underline\blue{Solution:-}$

Let $O$ be the starting point.

From $O$ Abhay drives 4km.

Let us assume that after driving 4km, Abhay reaches point $A$. So,

$OA=4km.$.

From A, Abhay drives 3km due east.

Let us assume that after driving 3km due east, abhay reaches point $B$.So,

$AB=3km.$

Now, we have to find the distance between starting point and terminating point.

Here, the distance between starting point and the ending point is calculated by using Pythagoras Theorem.

When abhay drives from A to B,

$\angle OAB=90\degree$.

So, in $\Delta OAB$,we can apply Pythagoras Theorem. Therefore, we get,

$OB^{2}=OA^{2} + AB^{2}$

$\implies OB=\sqrt{4^{2}+3^{2}}$

$\implies OB=\sqrt{25}\:km$

$\implies OB=5km$

Hence, the displacement between the starting point and terminating point is 5km.

$\star\:\:\:\bf\large\underline\blue{Answer:-}$

• The distance between the starting point and terminating point is 5km.