Math, asked by ritudua79, 2 months ago

Abhay is 6times as old as Ajay.five years from now abhay will b two less than seven times ajay present age .find their present and ages after five years​

Answers

Answered by judith0209
1

Answer:

Check explanation.

Step-by-step explanation:

Let Ajay's present age be x years

Then, Abhay's present age will be 6x years.   (Abhay is 6 times Ajay's age)

Now, Abhay's age after 5 years = 6x + 5

6x + 5 = 7x - 2---------(*remember it is Ajay's PRESENT age)

5 + 2 = 7x - 6x

7 = x

Therefore, Ajay's present age is 7 years while Abhay's present age is 6x7=42 years.

After 5 years,

Ajay will be 7+5=12 years and Abhay will be 42+5=47 years old.

Hope it helped : )

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