Question

Abhay Jogs from one end A to other end B on a straight 300m road in 2 min 30 sec and then turns around and jogs 100m back to point C in another 1 min. What are Abhay's average speed and velocity in jogging :

From A to B

From A to C

Answer 1

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Solution : From A to B


Total distance travelled = 300 m

Total Time Taken = 2 min 30 sec = 150 s


We know ; Average Speed = $\frac{Total\:Distance}{Total\:Time}$


=》$\frac{300m}{150s}$


=》 2 m/s

So, the average speed from A to B is 2 m/s.


Average Velocity = $\frac{Total\:Displacement}{Total\:Time}$



=》 $\frac{300m}{150s}$


=》 2 m/s

So, the average velocity from A to B is 2 m/s.



From A to C


Total distance travelled = 300 m + 100m = 400m

Total Time taken = 150s + 60s = 210s


Average speed = $\frac{Total\:Distance}{Total\:Time}$



=》 $\frac{400m}{210s}$.



=》 1.9 m/s


So, the average speed from A to C is 1.9 m/s.


Now;

Displacement = ( 300 - 100 )m = 200m

Total Time taken = 150s + 60s = 210 s


Average Velocity = $\frac{Total\:Displacement}{Total\:Time}$



=》 $\frac{200m}{210s}$



=》 0.95 m/s




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Hope this helps. . . . . . ☺☺