Question

Abhay Jogs from one end A to the other end B on a straight road 300m in 2 mins 30 secs and then turns around and jogs 100m back to point C in another 1 min . What are Abhay's average speed and average velocity in jogging :

(a) From A to B
(b) From B to C.

Answer 1

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(a) From A to B
Total distance travelled (s) = 300 m

Total Time taken (t) = 2 min 30 sec
= 150 s

Average Speed = $\frac{Total\:distance}{Total\:Time}$

= $\frac{300m}{150s}$

= 2 m/s
So, the average speed from A to B is 2 m/s.

Average Velocity = $\frac{Displacement}{Time\:Taken}$

= $\frac{300m}{150s}$

= 2 m/s
So,the average velocity from A to B is 2 m/s.

(b) From B to C
Total distance travelled = 300 m +100m = 400m

Total Time taken = 150s + 1 min = 150s + 60s = 210s

Average speed = $\frac{Total\:Distance}{Total\:Time}$

= $\frac{400m}{210s}$

= 1.9 m/s
So, the average speed from B to C is 1.9 m/s

Now, Displacement = (300-100) = 200m

Total Time = 2 min 30 s + 1 min = 210s

Average Velocity = $\frac{Displacement}{Time\:Taken}$

= $\frac{200m}{210s}$

= 0.95 m/s

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Hope this helps. . . . . . . ☺☺