Question

Abhay's age after six years will be three-
seventh of his father's age at present.
Find present age of father, if present age
of father is 4 more than three times of
Abhay's present age.​

Answer 1

Father's present age is 49 years.

• Let fathers present age be x and Abhay's present age be y.
• Now it is given that Abhay's age after six years will be three-seventh of his father's present age.

y + 6 = $\frac{3}{7}$x

7y + 42 = 3x

3x - 7y = 42  (Equation 1)

• Now, present age of father is 4 more than three times Abhay's present age.

x = 3y + 4

x - 3y = 4  (Equation 2)

• Solving equation 1 and 2 we get,

• Multiplying equation 1 by 3 and equation 2 by 7  , we get

9x - 21y = 126   (Equation 3)

7x - 21y = 28     (Equation 4)

• Subtracting equation 4 from 3, we get

2x = 998

x = 49

• Father's present age is 49 years.