Question

Abhi bahut questions h to dusro k answers report mat karo.....xD​

Answer 1

Answer:

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I). 3x+1

Put x= - 1/3

= 3×(-1/3) +1

= - 1+1

=0

0 zeros of the polynomial 3x+1.

2.)5x-pi

Put x =4/5

P(x) = 5×4/5-pi

= 20-pi

Is the zeroes of the polynomial.

3.x²-1

Put x= 1

P(x) = 1²-1

= 1-1

=0

Then putting x=-1

=-1²-1

=1-1

=0

Zero is the zeroes of the polynomial...

Answer 2

Answer:

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1) p(x)=3x+1,x= -1/3

$3( \frac{ - 1}{3} ) + 1 \\ \\ \frac{ - 3}{3} + 1 \\ \\ \frac{ - 3 + 3}{3} \\ \\ \frac{0}{3}$

$(3) \\ \\ (1) \: {x}^{2} - 1 \\ { - 1}^{2} - 1 \\ 1 - 1 = 0 \\ \\(2) \: {1}^{2} - 1 = 0$

$(5) \\ \\ {0}^{2} = 0$