Math, asked by saikatsingh8758, 1 year ago

Abhi bought two articles for rs 624. He sold one at a loss of 14% and the other at a profit of 14%

Answers

Answered by TanikaWaddle
1

cost price of first article is  Rs. 355.68

cost price of second article = Rs. 268.32

Step-by-step explanation:

Abhi bought two articles for rs 624 we need to find the cost price of each item if selling price of both the items are same .

let the cost price of first article be x

then cost price of second article = (624-x)

loss % on first article = 14%

profit % on second article = 14%

according to the question

the selling price of both the items are equal

then,

\frac{100-14}{100} \times x = \frac{100+14}{100}\times (624-x)

\frac{86}{100} \times x = \frac{114}{100} \times (624-x)\\

86 x = 114(624-x)

86 x = 71136 - 114 x

86x+ 114x = 71136

200x = 71136

x= \frac{71136}{200}

x = 355.68

hence,

cost price of first article is  Rs. 355.68

then cost price of second article = 624- 355.68 = Rs. 268.32

#Learn more:

A sells an article to B at a profit of 20%. B sells it to C at a profit of 4%.what does it cost A if C has paid Rs 624

https://brainly.in/question/3910732

Similar questions