Hindi, asked by sankar66kumar, 11 months ago

Abhi bought two articles for rs 624. He sold one at a loss of 14% and the other at a profit of 14% if selling price of both the articles are equal then the difference of their cost price is

Answers

Answered by Anonymous
0

Difference between the cost price of the two articles is- Rs. 87.36.

Let the cost price of first article be X. Cost price of second article will be (624-x). Formula with respect to profit% is-

SP = (100+Profit%)/100*CP

Formula with respect to loss% is- SP = (100-Loss%)/100*CP

Selling price of both the articles is same, as given in question. Hence keeping the values in equation -

{100 - 14/100}*(X) = {100 + 14/100}*(624-x)

0.86x = 1.14(624-x)

0.86x = 711.36 - 1.14x

2x = 711.36

X = 355.68

Hence, cost price of first article is - 355.68 Rs.

Cost price of second article will be calculated by = 624-355.68

= Rs. 268.32

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