Abhi is twice as old as his daughter.
Five years ago, his age was four times
his daughter's age. If the present age of
the daughter is x years, then :
(1) 2(x-5) = 4(2x + 5)
(2) 248-5) = 4(2x-5)
(3) 4(x-5)=2x-5
(4) 4(x+5) = 2(2x - 5)
Answers
Answered by
1
Answer:
answer is (3)
Step-by-step explanation:
present
present age of daughter is x
abhi is twice as old as his daughter =2x
5 years ago
daughter age is x-5
abhi age is 2x-5
abhi age is 4 times his daughter age (daughter age = x-5)
equating
4(x-5)=2x-5
Answered by
0
Answer:
The answer should be the 3rd option
Step-by-step explanation:
And as for explanation ,
As we know daughter is x years old.
So , abhi will be twice = 2x
Now 5 years ago,
Age of daughter = (x -5)
Age of abhi = (2x-5)
And the relation is Abhi's age is 4 times the age of daughter
Therefore ,
(2x-5) = 4(x-5)
=> 4(x-5) = (2x-5)
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