Math, asked by suraj27kmr, 4 months ago

Abhi is twice as old as his daughter.
Five years ago, his age was four times
his daughter's age. If the present age of
the daughter is x years, then :
(1) 2(x-5) = 4(2x + 5)
(2) 248-5) = 4(2x-5)
(3) 4(x-5)=2x-5
(4) 4(x+5) = 2(2x - 5)​

Answers

Answered by chinnadarling162
1

Answer:

answer is (3)

Step-by-step explanation:

present

present age of daughter is x

abhi is twice as old as his daughter =2x

5 years ago

daughter age is x-5

abhi age is 2x-5

abhi age is 4 times his daughter age (daughter age = x-5)

equating

4(x-5)=2x-5

Answered by AyushSingh2003
0

Answer:

The answer should be the 3rd option

Step-by-step explanation:

And as for explanation ,

As we know daughter is x years old.

So , abhi will be twice = 2x

Now 5 years ago,

Age of daughter = (x -5)

Age of abhi = (2x-5)

And the relation is Abhi's age is 4 times the age of daughter

Therefore ,

(2x-5) = 4(x-5)

=> 4(x-5) = (2x-5)

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