Abhi takes 40% more time than Aashu to complete the work. if Aashu works For x days and after that the remaining work is completed by abhi in X + 4 days then the ratio of the work done by ashu and abhi is 7:9.find in how many days abhi will complete the work alone?
Answers
Answered by
0
Answer:
Abhi take = 16 Days to complete work
Step-by-step explanation:
Abhi takes 40% more time than Aashu to complete the work.
Let say Ashu Take = D days to complete work
=> Abhi Takes = D = (40/100)D = 1.4D Days to complete work
Ashu 1 day work = 1/D
Abhi 1 day Work = 1/1.4D
Ashu x days work = x/D
Abhi x + 4 Days work = (x + 4)/1.4D
x/D : (x + 4)/1.4D :: 7:9
=> 1.4x/(x + 4) = 7/9
=> 12.6x = 7x + 28
=> 5.6x = 28
=> x = 5
x/D + (x + 4)/1.4D = 1
=> 1.4x + x + 4 = 1.4D
=> 2.4x + 4 = 1.4D
=> 2.4*5 + 4 = 1.4D
=> 16 = 1.4D
Abhi take = 16 Days to complete work
Answered by
1
Answer:
40%= 2/5
Abhi Ashu
7 : 5 (time ratio)
5 : 7 (efficiency ratio)
Total work = 7x+5(x+4)= 12x+20
7x/(5x+20)= 7/9
9x = 5x+20
4x = 20
X = 5
TW = 60+20= 80
Abhi's time = 80/5= 16 days
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