Abhilash travels to his friend house in 6½ hour at the speed of 50 km/hour but on his return journey he cover the same distance in 5 hours what is the his speed on return journey.
please do in process if you will give the correct answer it will very helpful for me.
Answers
Answered by
1
Answer:
Normal speed=40 kmph
Increased speed by 50%=40*150/100=60 kmph
Let the distance be 120 km
Time taken from A to B=120/40=3 hrs
Time taken from B to A=120/60=2 hrs
Total time taken=3+2=5 hrs
Total distance covered=120+120=240 km
Average speed=240/5=48 kmph
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Answered by
0
Answer:
ANSWER
Let the total distance travelled be x km Then total time taken =
x/3 x/3 x/3
+ +
10 20 60
X
30
+
180
6x + 3x + x
180
X
x/18
10x
180
18
km/hr 18 km/hr
Total distance travelled
Total time taken
=
hrs Then average speed:
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