Question

Abhimanyu and supreet can together finish a work in 50 days. They worked together for 35 days and then supreet left. After another 21 days, abhimanyu finished the remaining work. In how many days abhimanyu alone can finish the work?

Answer 1

given :

let the total days Abhimanyu needed be x

he completed 15 days work in 21 days alone

than the total no. of days that he needed to complete the work alone ~ 15 : 21 = 50 : x

~ 15/21 = 50/x

~ 15x = 50 × 21

~ 15x = 1050

~ x = 1050/15

~ x = 70

so Abhimanyu alone can finish the work at 70 days

Answer 2

Answer:

Step-by-step explanation:

~ 15/21 = 50/x

~ 15x = 50 × 21

~ 15x = 1050

~ x = 1050/15

~ x = 70