Abhimanyu has 3 times as many Rs.2 coins as he has Rs. 5 coins. If the total money he has is Rs 77, how many coins of each denomination does he have?
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Answer:
5×x+ 2×3x =77
5x+ 6x=77
11x=77
x=7
Rs5= 7 coins
Rs.2=3×7=21coins
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