Abhimanyu has Rs300 in denomination of Rs1,Rs2 and Rs5 notes. The number of Rs2 notes is 3 times the number of Rs5 notes.If the total number of notes is 160,how many notes of each denomination are with him?
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Let number of Rs5. coins = x
Then number of Rs2. coins = 3x
number of Re 1. coins = 160 - 4x
Since total amount = Rs.300
5x + 6x + 160 - 4x = 300
ie, 7x = 140
implies x = 140 / 7 = 20
Therefore ,
number of Re1 coins = 160 - 4*20
= 160 - 80 = 80
number of Rs2 coins = 3x = 3*20 = 60
number of Rs.5 coins = x = 20
Then number of Rs2. coins = 3x
number of Re 1. coins = 160 - 4x
Since total amount = Rs.300
5x + 6x + 160 - 4x = 300
ie, 7x = 140
implies x = 140 / 7 = 20
Therefore ,
number of Re1 coins = 160 - 4*20
= 160 - 80 = 80
number of Rs2 coins = 3x = 3*20 = 60
number of Rs.5 coins = x = 20
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