Math, asked by reenkri2017, 1 year ago

Abhimanyu invested Rs 100000 at 13 % per annum compounded annually. Find the following: (i) The amount standing to his credit at the end of the second year. (ii) The interest for the third year.

Answers

Answered by rio123491
7

Answer:

Given ; 

• Amount = ₹1,00,000

• Rate = 13% p.a.

• Time = 3 years ( according to understanding )

__________________________

Now , Asked is ; 

(i) The amount standing to his credit at the end of the second year. 

(ii) The interest for the third year.

__________________________

(i) First Question ; 

• We know the Formula ;-

=> A = P ( 1+R x 1/2 ÷ 100 )2n

=> A = 100000 ( 1 + 13 x 1/2 ÷ 100 )4

=> A = 100000 ( 1 + 6.5/100)4

=> A = 100000 ( 106.5/100)4

=> A = 100000 x 106.5/100 x 106.5/100 x 106.5/100 x 106.5/100 

=> A = ₹ 128,646.63

• Hence , the amount standing to his credit at the end of the second year is ₹ 128,646.63.

________________________

(ii) Second Question ;- 

• According to the formula above discussed ;- 

=> A = P ( 1+R x 1/2 ÷ 100 )2n

=> A = 128,646.63 ( 1 + 6.5 /100 )2

=> A = 128,646.63 x 106.5/100 x 106.5/100

=> A = ₹ 145,914.23

• We know that ; 

=> CI = A - P 

=> CI = 145,914.23 - 100000 

=> CI = ₹ 45,914.23

Hence , 

The CI = ₹ 45,914.23 and as above taken interest for the third year is 128,646.63.

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Answered by Anonymous
3

Answer:

Answer:

Given ; 

• Amount = ₹1,00,000

• Rate = 13% p.a.

• Time = 3 years ( according to understanding )

__________________________

Now , Asked is ; 

(i) The amount standing to his credit at the end of the second year. 

(ii) The interest for the third year.

__________________________

(i) First Question ; 

• We know the Formula ;-

=> A = P ( 1+R x 1/2 ÷ 100 )2n

=> A = 100000 ( 1 + 13 x 1/2 ÷ 100 )4

=> A = 100000 ( 1 + 6.5/100)4

=> A = 100000 ( 106.5/100)4

=> A = 100000 x 106.5/100 x 106.5/100 x 106.5/100 x 106.5/100 

=> A = ₹ 128,646.63

• Hence , the amount standing to his credit at the end of the second year is ₹ 128,646.63.

________________________

(ii) Second Question ;- 

• According to the formula above discussed ;- 

=> A = P ( 1+R x 1/2 ÷ 100 )2n

=> A = 128,646.63 ( 1 + 6.5 /100 )2

=> A = 128,646.63 x 106.5/100 x 106.5/100

=> A = ₹ 145,914.23

• We know that ; 

=> CI = A - P 

=> CI = 145,914.23 - 100000 

=> CI = ₹ 45,914.23

Hence , 

The CI = ₹ 45,914.23 and as above taken interest for the third year is 128,646.63.

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