Abhinav moves 4km on south direction,then he moves 3km in east direction. How far is he from the starting point? (A)5km (B)1km (C)3 km (D) 4km.
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Answered by
3
Answer:
4²+3²=x²
distance from starting point = x
pythagoras theorem
16+9=x²
25=x²
5×5=x×x
X=5
so the distance from starting point is 5km
Answered by
0
Option a
Hope it's help you
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