Abhishek and Abhinandan together can complete a work in 20 days. Abhinandan started to work alone and
completes 2/3 work and remaining work is completed by Abhishek alone. They completed the work in total
39 days. Find in how many days Abhinandan alone can complete the work it he works for whole numberof
days
Answers
Answer:
if 39 is 3part of work
then one part of work will be completed in =39/3=13 days
the work done by Abhinandan is 2part
13*2= 26days
hence answer is 26days
alternate method to solve this problem
hope this answer useful to you and pls make me brainlist pls
Solution:-
Let say Abhinandan alone can complete work in A days
Work done by Abhinandan in 1 day = 1/A
abhishek and abhinandan together complete a work in 20 days
abhishek and abhinandan together complete a work in 1 day = 1/20
Work done by abhishek in 1 day = 1/20 - 1/A = (A -20)/20A
Let say Anhinandan work for D days
then abhishek work for 39 - D days
Work done by abhinandan = D/A
work done by abhishek = (39-D)×(A -20)/20A
D/A = 2/3 => D = 2A/3
(39-D)×(A -20)/20A = 1/3
=> 3(39 - D)(A -20) = 20A
using D = 2A/3
=> 3(39 - 2A/3)(A -20) = 20A
=> (117 - 2A)(A - 20) = 20A
=> -2A² + 117A + 40A - 2340 = 20A
=> -2A² + 137A - 2340 = 0
=> 2A² - 137A + 2340 = 0
=> 2A² - 72A -65A + 2340 = 0
=> 2A(A - 36) -65(A - 36) = 0
=> (2A -65)(A -36) = 0
=> A = 65/2 A = 36
Taking only whole number answer
Abhinandan alone can complete the work in 36 Days
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@GauravSaxena01