Abhishek and his friend go for a morning walk in a circular park whose circumference is 125m. they start from the same point and walk in opposite directions at 3.5kmph and 2.75kmph respectively. after how much time will they meet for the first time?
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Consider time be t.
It would be same to meet both of them, however their speed and distance may vary.
Now consider these distances be x and y respectively. And similarly their respective speeds be 3500mph and 2750mph.
Now this generates two equations, first as totality of distance as 125 m (thus, x+y=125) and another is equality of time (I.e. x/3500 = y/2750)
Solving both of these equations, we get x=70m and y=55m.
And time would then be x/3500 hrs. = 70/3500 hrs. = 1/50 hrs.
This means 60/50 min. Or about 1.2 minutes.
Converting time into seconds would be 1.2*60 sec. I.e. 72 seconds.
After 72 seconds both of the guys will meet each other.
Brilliant question. Thanks for asking.
It would be same to meet both of them, however their speed and distance may vary.
Now consider these distances be x and y respectively. And similarly their respective speeds be 3500mph and 2750mph.
Now this generates two equations, first as totality of distance as 125 m (thus, x+y=125) and another is equality of time (I.e. x/3500 = y/2750)
Solving both of these equations, we get x=70m and y=55m.
And time would then be x/3500 hrs. = 70/3500 hrs. = 1/50 hrs.
This means 60/50 min. Or about 1.2 minutes.
Converting time into seconds would be 1.2*60 sec. I.e. 72 seconds.
After 72 seconds both of the guys will meet each other.
Brilliant question. Thanks for asking.
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