Question

Abhishek is 6 years older than Jagadish. Six years ago Abhishek was twice as old as Jagadish. Write down the situation in algebraic expression and find how old is each now. Abhishek is 6 years older than Jagadish. Six years ago Abhishek was twice as old as Jagadish. Write down the situation in algebraic expression and find how old is each now.

Answer 1

Answer:

$Let x = Jagdishs present age \\x+6 = Abisheks age now\\x-6 =Jagdishs age 6 years ago\\(a+6)- 6 = Abisheks age 6 years ago\\Since six years ago Abishek was twice as old as he\\(x+6)-6=2x-12\\x+6-6=2x-12\\-x=-12\\x=\frac{-12}{-1} \\x-12$

Answer 2

Answer:

The answer to your question is as follows:

Step-by-step explanation:

Let present age of Jagadish be x.

Let present age of Abhishek be x +6.

6 years ago,

Age of jagadish = x -6

Age of Abhishek = 2(x -6)

According to question

= x - 6 = 2(x-6)

= x - 6 = 2x - 12

= x-2x = -12 + 6

= -x = -6

= x = 6

Therefore,

Present age of Jagadish = 6 years

Present age of Abhishek = 12 years

I hope it is helpful.