Math, asked by spacelover123, 8 months ago

Abhishek is 6 years older than Jagadish. Six years ago Abhishek was twice as old as Jagadish. Write down the situation in algebraic expression and find how old is each now. Abhishek is 6 years older than Jagadish. Six years ago Abhishek was twice as old as Jagadish. Write down the situation in algebraic expression and find how old is each now.

Answers

Answered by masterbrain123
4

Answer:

Let x = Jagdishs present age \\x+6 = Abisheks age now\\x-6 =Jagdishs age 6 years ago\\(a+6)- 6 = Abisheks age 6 years ago\\Since six years ago Abishek was twice as old as he\\(x+6)-6=2x-12\\x+6-6=2x-12\\-x=-12\\x=\frac{-12}{-1} \\x-12

Answered by Anonymous
3

Answer:

The answer to your question is as follows:

Step-by-step explanation:

Let present age of Jagadish be x.

Let present age of Abhishek be x +6.

6 years ago,

Age of jagadish = x -6

Age of Abhishek = 2(x -6)

According to question

= x - 6 = 2(x-6)

= x - 6 = 2x - 12

= x-2x = -12 + 6

= -x = -6

= x = 6

Therefore,

Present age of Jagadish = 6 years

Present age of Abhishek = 12 years

I hope it is helpful.

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