Math, asked by anshbhadauria93, 3 months ago

Abhishek is x years old. His
brother's age is 3 years more
than twice his age. What is the
difference in their ages?​

Answers

Answered by AnkitaSahni
1

The difference in their ages is (x + 3) years.

Given:

Abhishek is x years old. His brother's age is 3 years more than twice his age.

To Find:

The difference in their ages.

Solution:

To find the difference in their ages we will follow the following steps:

According to the question:

Age of Abhishek = x years

And,

His brother's age is 3 years more than twice his age, which is equal to

2x + 3 years

Now,

The difference in their ages can be written as:

age of Abhishek's brother - age of Abhishek =

(2x + 3) - x = x + 3 \: years

As Abhishek's brother is older than him that's why we subtract the age of Abhishek's age from the age of Abhishek's brother.

Henceforth, the difference in their ages is (x + 3) years.

#SPJ1

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