Question

Abhishek travels 4 km towards North and then travels 5 km eastwards. He then travels 10 km

rightwards and then 3 km to the left and finally 5 km northwards. How far is he approximately from

his original destination and in what direction?

A. 13.5 km, South-East

B. 15 km, South

C. 8 km, South-East

D. 18 km, South

​

Answer 1

(c) According to given information, the direction diagram is as follows:

Here, AE = BC = 9 km

∴ Required distance = SA + AE = 5 + 9 = 14 km .

Answer 2

Answer:

Abhishek traveled 8 Km, South-East from his original starting point.

Step-by-step explanation:

Step(1): Let Abhishek starts his journey from 'O'. He travels to point 'A' for 4 Km towards the north direction.

Step(2): From point 'A' he then travels to point 'B' which is 5 Km towards eastwards.

Step(3): Let us think Abhishek takes some rest at point 'B' and starts his journey to point 'C' located at 10 Km towards his right i.e. he travels 10 Km towards the South.

Step(4): He then travels 3 Km to his left to point 'D' i.e. 3 km towards the East.

Step(5): At last from point 'D' he travels to hid destination 'E' which is located at 5 Km towards the North.

Now, we have to find the distance between points 'O' and 'E'

From Step(1), step(3), and step(5) we can conclude that point 'E' is 1 Km from point 'O' in the vertical direction.

And in the horizontal direction, the distance between the points 'O' and 'E' is 5 Km + 3 Km.

hence, the distance between 'O' and 'E' is $\sqrt{1^2 + 8^2}$ ≈ 8 Km

Therefore, he traveled 8 Km, South-East from his original starting point.

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