Abigail's airplane trip took 4 hours. For half (third/fourth) of that time,the airplane flew at a speed of 900km/h and for the rest of the time, it flew at a speed of 760 km/h. What distance did she travel?
PLEASE ANSWER FAST
Answers
Answered by
11
Answer:
6640 km
Explanation:
speed = distance/time
distance = speed * time
d1 has time = 2 hrs and speed = 900 km/h
d2 has time = 2 hrs and speed = 760 km/h
d1+d2 = (900+760)*(2+2)
distance = 1660 * 4
distance = 6640 km
Answered by
3
Answer:
6640 km
Explanation:
speed = distance/time
distance = speed * time
d1 has time = 2 hrs and speed = 900 km/h
d2 has time = 2 hrs and speed = 760 km/h
d1+d2 = (900+760)*(2+2)
distance = 1660 * 4
distance = 6640 km
Similar questions