Question

Abigail wants to find three consecutive even integers whose sum is 4 times the smallest of those integers. She lets n represent the smallest integer and then writes this equation.

n+(n+2)+(n+4)=4n
Question 1
Part A

Solve the equation.

Enter the correct answer in the box.

Answer 1

Answer:

Therefore, the three consecutive integers are 6,8,10.

Step-by-step explanation:

Given equation is:-

n+(n+2)+(n+4)=4n

3n+6=4n

4n-3n=6

n=6