Question

ABllCD find the value of unknown quantities. part vi,vii and viii​

Answer 1

Answer:

6)draw a line from B to D,which is perpendicular to both AB and CD,

then,<DBC=60,<BDC=40,X=180-(60+40)=80degrees,

7)draw a line from B to D,which is perpendicular to both AB and CD,

then <BDM=50,<DBM=X-90,given,<DMB=90,

Therefore,50+X-90+90=180,

=>X=130 degrees,

8)draw a line from A to C,such that AC is Perpendicular to both AB and CD,

then,<CAM=50,<ACM=40,X=180-(50+40)=90degrees.

Hope it helps u