Physics, asked by ishitasingh12395, 7 months ago

Abody is projected horizontally from the top of a tower with initial velocity 18 ms-'. It hits the ground at angle
45° What is the vertical component of velocity when it strikes the ground?

Answers

Answered by abhishekyadav320021

0

Answer:

Ux =9√2 , Ux =9√2

Range find

R = 2UxUy÷g

R = 2*9√2*9√2÷10

R. = 324/10

t. = d÷v

t = 324/10÷18

t =1.8 sec

Vy = Uy +gt

Vy = 0 +10*1.8

Vy = 18 m/s Answer

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