About 5 % of the power of a 100 W light
bulb is converted to visible radiation.
What is the average intensity of visible
radiation at a distance of 1 m from the
bulb ? Assume that the radiations are
emitted isotropically and neglect
reflection.
1 0.2 Wm - 2
2) 0.4 Wm-2
3) 0.8 Wm-2
4) 1.6 Wm-2
Answers
Answered by
1
Answer:
Explanation:
(a)
Power of visible radiation P
′
=5×100/100=5W
I=P
′
/4πd
2
=0.398W/m
2
; d=1m
(b)
Power of visible radiation P
′
=5×100/100=5W
I=P
′
/4πd
2
=0.004W/m
2
; d=10m
November 22, 2019
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