About 5% of the power of a 100W light bulb is converted to visible radiation. What is the average intensity of visible radiation at a distance of 10m from the bulb?
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the answer 100 kg weight means the answer is 0
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Power of visible radiation, P′=5×100100=5W
d=10m
Hence, intensity of radiation,I=P′4πd2
=54π(10)2=0.0039
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