Question

about finding square roots,

someone's go far no coping​

Answer 1

Answer:-

The inverse( opposite) operation of addition and subtraction and the Inverse Operation of multiplication is division similar finding the square root is the inverse operation of squaring.

We have,

$1 {}^{2} = 1..therefore \: square \: root \: of \: 1 \: is \: 1 \\ 2 {}^{2} = 4..therefore \: square \: root \: of \: 4 \: is \: 2 \\ 3 {}^{2} = 9..therefore \: square \: root \: of \: 9 \: is \: 3$

Answer 2

For example let us take a quadratic equation x²-5x+6 = 0 which has factors 2 and 3 (you can verify this by factorization method).

As you know, (a+b)² = a²+2ab+b²

Hence, if you take x² = a²(x = a) and -5x as 2ab, you get b= -5x/2a = -5x/2x = -5/2

(x-5/2)²=x²-5x+(-5/2)2= x²-5x+25/4

In order to get x2-5x+6 from x2-5x+25/4, you have to add it by 6-(25/4)= 24/4- 25/4 = -1/4

Hence, you can express x²-5x+6 = 0 as: (x-5/2)²+(-1/4) = (x-5/2)² - 1/4 = 0

(x-5/2)² = 0+1/4 = 1/4

(x-5/2) = √1/4 = ± 1/2

x = -1/2 + 5/2 = 4/2 = 2

0r,

x = 1/2 + 5/2 = 6/2 = 3