above figure shows the distance time graph of two trains which starts moving simultaneously in the same direction from the graph find :
(a) how much B is ahead of A when motion starts
(b) what is the speed of B?
(c) when and where A will catch B.
(d) what is the difference in speed of A and B
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20
Answer & Explanation:
A. The Train B is 80 km away from Train A when it starts to move.
B. Distance = 120 km
Time = 2 hrs
Speed = Distance/Time
= [120/2] km/hr
= 60 km/hr
C. After 2 hours of motion, Train A catches Train B at 120 km away from their starting point.
D. Speed of Train B = 120 km/hr
Train A,
Distance = 120 km
Time = 2 hrs
Speed = D/T
= [120/2] km/hr
= 60 km/hr
Difference in speed= [120-120] km/hr
= 0 km/hr
[Note: This was the difference in speed at 2 hours but after that, the speed of Train A increases and in case of Train B, speed decreases]
Hope this helps.
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4
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