Abox contain 4 red and 3 black balls. One ball is taken away from the box. After that two balls are drawn at random and both found red, what is the probability that the first ball taken aways was also red ?
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Answer:
Total 4 red and 3 black balls.
given: 2nd & 3rd balls are red. that means that the possibility of getting 1 red ball in 1st chance is out of 2 remaining red balls.
so probability of getting 1 red ball from 2 red balls + 3 black balls = 2/5
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Answer:
2/5.
Step-by-step explanation:
Total 4 red and 3 black balls. given: 2nd & 3rd balls are red. i.e. possibility of getting 1 red ball in 1st chance is out of 2 remaining red balls. ∵ These are two independent events probability of getting 1 red ball from 2 red + 3 black balls is [2C1/5C1] = 2/5.
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