Question

Abox contains 2 dozens mangoes, 1/2 dozen apples and 1 dozen oranges. Find the probability of the following events if one of the fruits is picked up from the box at random. i) It is a mango fruit. ii) It is an apple fruit. iii) It is an orange fruit.
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Answer 1

Answer:

Whenever it is not explicity mentioned that fruit and distint, We take them as identical. 0 or more orange can be selected from 4 identical oranges in (4+1)=5 ways. 0 or more apples can be selected from 5 identical apples in (5+1)=6 ways.

0 or more mangoes can be selected from 6 identical mangoes in 7 ways.

∴ Total no. of ways in which all of three types of fruits can be selected (the no. of any type of fruits may also be 0), 

5×6×7=210,

But in these 20 selection, there is one selection where all fruits are 0, hence we reduce 1 selection.

∴ the required no. =210−1=209  

Step-by-step explanation:

hope you help its

Answer 2

Answer:

1) 12/21

2)1/7

3)6/21

Explanation:

Let P(M),P(A) and P(O) denote the probability of getting mangoes,apples and oranges respectively.

Here, n(M) =2*12=24

n(A)=1/2*12=6

n(O)=12

Also,n(S)=42

Now,P(M)=n(M)/n(S)=24/42=12/21

P(A)=n(A)/n(S)=6/42=1/7

P(O)=n(O)/n(S)=12/42=6/21