ABparllell toDC P is the midpoint of prove that p is the midpoint of AC
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We have AE=AD and CE=BD.
Adding, we get AE+CE=AD+BD
⇒AC=AB.
In triangles AEB and ADC, we have
AE=AD ....... (given);
AB=AC ....... (proved);
∠EAB=∠DAC, (common angle).
By SAS postulate △AEB≅△ADC.
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