ABQC and PQRS are parallelograms. Find x.
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Answer:
x=20°
Step-by-step explanation:
A=CQB=80° (opp angles of ||gm are equal)
similarly, P=SRQ=60°
SRQ+QRA=180° (Linear pair)
60°+QRA=180°
QRA=120°
QRA=RQP=120° (Alternate angles)
PQC+CQR+RQB=180° (linear pair)
120°-x+x+80°-x=180°
200-x=180°
x=20°
feel free to correct me if I'm wrong
kinda wrote this in a hurry:)
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