ABQC and PWRS are parallelogram find x
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2
Step-by-step explanation:
In ll gm ABQC , angle abq = 180-80
=100 (because CA and QB is a ll line and AB is the transverse line )
In triangle CRQ ..... angle x + angle crq + angle rcq = 180
angle crq = 60 ( opposite angle of a llgm is equal )
angle rcq = angle ABQ =100
Thus , angle x + 60 + 100 = 180
and thus , angle x = 180 - 160
= 20
Answered by
0
Answer:
20°
Step-by-step explanation:
SPQ +PQR=180° ( CO INTERIOR)
60°+PQR=180°
PQR=180-60°
PQR =120°
RAB +ABQ =180° (CO INTERIOR)
QBA =100°
PQR =80 °
NOW,
PQC+X°+RQB=200 °
X° = 200°- PQC-RQB
X° = 200 - 180
X=20°
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