Math, asked by pundirkajal12, 9 months ago

ABQC and PWRS are parallelogram find x​

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Answers

Answered by reenaroy2878
2

Step-by-step explanation:

In ll gm ABQC , angle abq = 180-80

=100 (because CA and QB is a ll line and AB is the transverse line )

In triangle CRQ ..... angle x + angle crq + angle rcq = 180

angle crq = 60 ( opposite angle of a llgm is equal )

angle rcq = angle ABQ =100

Thus , angle x + 60 + 100 = 180

and thus , angle x = 180 - 160

= 20

Answered by priyanshu08kr
0

Answer:

20°

Step-by-step explanation:

SPQ +PQR=180° ( CO INTERIOR)

60°+PQR=180°

PQR=180-60°

PQR =120°

RAB +ABQ =180° (CO INTERIOR)

QBA =100°

PQR =80 °

NOW,

PQC+X°+RQB=200 °

X° = 200°- PQC-RQB

X° = 200 - 180

X=20°

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